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Sixth Grade Challenging Math

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6-67)   Answer

                      0.285R2

Solution: Area of a quarter circle is 1/4 *3.14*R2, Area of the right triangle formed by 2 lines labeled "R" is 1/2R2

Area in red = Area of a quarter circle - Area of a triangle = 1/4 *3.14*R- 1/2R2 = 0.285R2

 

 

 
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