Sixth Grade Challenging Math
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6-88) Answer
17
solution #1 : Start with 3 and count by 6 until 99
3, 9, 15, 21, 27, 33, 39, 45, 51, 57, 63, 69, 75, 81, 87, 93, 99
Solution #2:
(99-3)/6 = 16. Since there is one number at both ends of the series, the answer is 16+1 =17