Solution: Think the weight of the entire pile of fertilizer is 1. So after the first day, there is 1 - 2/5 = 3/5 left. The amount transferred on the 2nd day is: (1 - 2/5) x 3/4; and the remaining is: (1 - 2/5 - (1-2/5) x 3/4) = 3/20, which is 1200 pounds. The answer is: 1200 ÷ (3/20) = 8000 lbs

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