HomeContact UsParents CornerAbout UsWorksheets
 1st Grade Math
 2nd Grade Math
 3rd Grade Math
 4th Grade Math
 5th Grade Math
 6th Grade Math
 7th Grade Math
 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 


7th Grade Challenging Math

-------------------------------------------------------------------------

7-64)   Answer

          6 spiders and 14 iguanas
 

 

Solutions: Assume there are 20 iguanas and no spiders. There would be 80 legs. So there are 18 extra legs (104 - 80 =24).  Since spiders have 8 legs each (4 more than each iguana has), it would take 6 spiders to make up for the extra 24 legs.


 

 
Free challenging math problems for Kids (1st grade, 2nd grade, 3rd grade, 4th grade, 5th grade, 6 grade and 7th grade) 
Copyright (C) 2010-2017 www.MathTop10.com